Why is the comma making difference in the output?

Question

print((lambda x: x**2 + 5*x + 4) (-4))
output:0
print((lambda x: x**2 + 5*x + 4), (-4))
output:<function <lambda> at 0×7ff8766b51f0> -4

Answer 1

In first , case you are calling lambda function with parameter -4 so returns -4**2 +5*-4 + 4 => 20-20 => 0

In second case, two arguments are different, no relation. First print lambda expression which returns generators, and followed by space separating -4.

Note: lambda expression is a functional expression.

Hope it helps..

Answer 2

, means both are different expressions for print() function

that's why it's printing the object of the function and -4 as integer