What is the missing part

Question

This is how suppose to be the output
55554
4443
332
21
1

This is my code here
#include <iostream>
using namespace std;

int main() {
for(int i=5;i>1;i--)
{ cout<<i;
for(int j=2;j<i;j++)
{
cout<<i;

}
cout<<i-1;
cout<<endl;
}
return 0;
}

But the out is
55554
4443
332
21

Answer 1

Bacani Rocelle M.

Just follow the previous pattern logic and initialise y with 5 and then decrement it

https://code.sololearn.com/cDHj1fIrwt1T/?ref=app

Answer 2

1) take i>=1 // instead of i>1
2) assign j = 1 , comment first cout.
Only print in loop.

Between, how last output is 1,... Is it not supposed to be 0?

Answer 3

Then take
1) i >= 1
And print
if(i-1>0)
cout<<i-1; // ok or not efficient?

Answer 4

A͢J if(i > 1 && x+1 >= i) 👍😎

Answer 5

Your loop stops at 2
Because your condition states
i > 1
So it 2 is the last num that is greater than 1 here

Thats why you need to do
i>=1
Or
i>0
To make it work

Answer 6

Yes the last output must 1

Answer 7

Bacani Rocelle M.
Yes, I also think that it is better to use the full conditional expression "if... else" than "continue", yes and the variable j is superfluous:
for(int i = 5, x = 0; i > 0;){
if(x < i){
if(i > 1 && x+1 >= i)
cout << i-1 << endl;
else cout << i;
x++;
} else {
i--;
x = 0;
}
}

//Or:
for(int i=5, j=0; i > 0;){
if(++j >= i){
j = 0;
if(--i==0) cout << 1;
else cout << i << endl;
}else cout << i;
}

Answer 8

Bacani Rocelle M. I edited the code.

If you want to address someone personally click on @ 😎

Answer 9

Bacani Rocelle M. I mean, do you want me to explain your code? 🤔

You need five lines means i>0.
You don't need the last value of i, so stop the loop if(i==1)break;
If the teacher forbade the use of "break" when solving this task, then change the condition to if(i != 1) cout<<i-1<<endl;

for(int i=5;i>0;i--){
cout<<i<<' ';
for(int j=2;j<i;j++)
cout<<i<<'-';
if(i==1)break;
cout<<i-1<<endl;
}

P. S: "In the end, you could just add cout to the end of your code cout<<1;"😉

Answer 10

this one works, u said only using for loop right?

#include <iostream>
using namespace std;

int main() {
for(int i=5;i>=1;i--)
{ cout<<i;
for(int j=2;j<i;j++)
{
cout<<i;

}
for(int k=i-1;k>0;k -= i) {
cout<<i-1<<endl;
}
}
return 0;
}

// edit : this code is not efficient, its better to use if statements

Answer 11

Solo

Same thing just way is different

Answer 12

Aj but our prof said that dont use break or continue just use loops

Answer 13

Thank you very much for the guide solo ill study this one

Answer 14

Solo ok if i cant figure out my code

Answer 15

Solo thank you for explaining

Answer 16

Please use this code

#include <iostream>
using namespace std;

int main() {
for(int i=5;i>=1;i--)
{
cout<<i;
for(int j=2;j<i;j++)
{
cout<<i;
}
if(i-1 > 0){
cout<<i-1;
}
cout<<endl;
}
return 0;
}

Answer 17

You could have just changed
; i>1;
to
; i>=1;
In the first for loop, and that would have given you the desired output.