C++ program to read (X) and then disting uish either X is an odd or even if number double operator

Answer 1

take input as string and take refrence to my code below

https://code.sololearn.com/c65XRCvhCtsO/?ref=app

Answer 2

Please help me

Answer 3

this stuff is in the lessons, if you are having trouble, feel free to read them another time.

checking if even or odd is done with x%2 == 0

what do you mean by "if number double operator"?

Answer 4

Double num;
Cin>>num;
if(num%2==0)
{
cout<<´´even´´;
}
else
{
Cout<<´´odd´´;
}

Answer 5

Like this how i can solve?

Answer 6

Younis Ahmad Yes, that's the way. Put it in Code Playground and test it.
But first double check:
1. The statements, types, etc., are lower case. There are no "Double", "Cin" or "Cout".
2. Use regular quotes in cout. Those fancy ones will give you a syntax error.