I can’t find the error!!! Exercise Shape in Java course

Question

When I execute the code I can’t pass the 3rd test

import java.util.Scanner;

abstract class Shape{
int width;
abstract void area();
}
//your code goes here
class Square extends Shape{
public Square(int side){
this.width=side;
}
public void area(){
System.out.println((int)Math.pow(width,2));
}
}

class Circle extends Shape{
public Circle(int radius){
this.width=radius;
}
public void area(){
System.out.println(Math.pow(width,2)*Math.PI);
}
}

Answer 1

Yes. Precision difference exists for other way..

You're welcome..

Answer 2

If I don’t cast in the square the output will be double while I’m searching an integer output. I tried to change in Circle area but it doesn’t work

Answer 3

This is the exercise Shape in the java course; when I execute the code the expected output is an integer for the square while for the circle there isn’t any limit as output

Answer 4

For square area() both ways are same. No difference. Both works.

For, circle area() I just checked in coach, it is working fine as I mentioned. Do check again..
System.out.println(Math.PI*width*width);

If not work, then post your update code with saving playground and share link...

Answer 5

public class Program{
public static void main(String[] args){
Scanner sc=new Scanner(System.in);
int side=sc.nextInt();
int radius=sc.nextInt();
Square square=new Square(side);
Circle circle=new Circle(radius);
square.area();
circle.area();
}
}
That’s the main part

Answer 6

Why you printing integer cast value only..? Don't cast.

For Circle area: try
System.out.print( Math.PI*width*width) ;

Answer 7

Oh. Ok fine it is. I only find change need in Circle area() output as I mentioned. There will exist a slight precision value difference. Try again my statement.

Answer 8

I alteady tried to change in the way you suggested me but it doesn’t work; I tried also change in the square area side*side instead of (int)Math.pow(side,2) but it doesn’t work

Answer 9

Ok now it’s work in the form Math.PI*width*width but not in the form width*width*MathPI
Thank you ☺️

Answer 10

Damn rounding!!! 😂

Answer 11

Hi

Answer 12

🦍🦍