Can anyone explain me why this code is giving 0 as a output

Question

#include <iostream>
using namespace std;

int main()
{
float purchaseAmount1, purchaseAmount2, purchaseAmount3;
float discount1, discount2, discount3;

// your code goes here
cin >> purchaseAmount1;
cin >> purchaseAmount2;
cin >> purchaseAmount3;
discount1 = (15 / 100) * purchaseAmount1;
discount2 = (15 / 100) * purchaseAmount2;
discount3 = (15 / 100) * purchaseAmount3;
cout << discount1 << endl;
cout << discount2 << endl;
cout << discount3 << endl;
return 0;
}

Answer 1

15 / 100

Here you are doing integer division, whatever fractal there was in result, will be truncated, and you only get the whole number. 15 / 100 0.15, but the .15 fractal will be truncated, and you only will get the 0 (zero)

Use floating point literal for generating the percentage

discount1 = ( 15.0 / 100 ) * purchaseAmount1; // notice 15.0 is a floating point value

Or, if the discount percentage is constant, you can directly calculate

discount1 = 0.15 * purchaseAmount1; // using floating point literal

const float percentage = 0.15f;
discount1 = percentage * purchaseAmount1; // using constant <percentage>

Answer 2

Thanks Ipang I got the answer