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I have a model field which is a Fileupload and I want to extract the file through the queryset how can I do that?

Hi Guys I don't know if I can get some django advice In my django project I have a model and i the model I have a field which is a model.Fileupload() then I get to uplaod a file, now I want to access that file via the django queryset

24th Nov 2022, 9:15 PM
Linda Mngadi
Linda Mngadi - avatar
4 odpowiedzi
+ 1
I will try that I was trying to access the file through queryset but I couldn't get what I actually want Thanks again 🤝🏽
3rd Dec 2022, 12:24 AM
Linda Mngadi
Linda Mngadi - avatar
0
If I got your question right, you are looking for url. class YourModel: its_file = FileField(upload_to=your_media_dir ... And then you access the file eg via your_model_instance.its_file.url See ( FileField ): https://docs.djangoproject.com/en/4.1/ref/models/fields/
28th Nov 2022, 6:45 PM
Fu Foy
Fu Foy - avatar
0
Hi, no it's not a url am looking for, the model field is Fileupload, then I uploaded a file from front-end now I want to extract the particular file using django queryset in the backend Am not sure if my statement is understandable Thank you for trying to help
1st Dec 2022, 12:55 PM
Linda Mngadi
Linda Mngadi - avatar
0
I'm not sure if I got you right, but if you are trying to access the file itself, not the model, you can do something like: import os os.open(path_to_media_dir + your_model.file.url)
2nd Dec 2022, 9:40 PM
Fu Foy
Fu Foy - avatar