How this statement in C is evaluated?

Question

I was asked to choose the output for this statement in C.
printf(6+"Hello World!");

Answer 1

I will add another hint to William Owens answer. The literal string "Hello World" evaluates as a pointer (char *). Think of the expression being evaluated in the context of pointer arithmetic.

Answer 2

Think about the indice numbering.

The first argument in the printf function is a pointer to a char.

Answer 3

W

Answer 4

Alhaaj [LESS ACTIVE] ,Close try running it in a main function and see the output, why do you think the output is slightly different?