help fixing my password detetcor code in python

Question

Hello, i dont know if thos was the appropriate place but im having trouble with my code saying the "break is outside the loop and all i can see is that my indentations are fine and it looks as though its in the if loop. what am i not seeing?

#password strength detector

import re, sys
print("""check how strong your password is.
it needs to be 8 characters long,
contain both upper and lowercase characters
and have at least one digit""")

def passWordDetect(x):
#8 characters long
text = re.compile(r"[a-zA-Z0-9.\%]{8,}")
text.search(x)
if text.search(x) == None:
print("Your password needs to be at least 8 characters long")
else:
break

#one upper and lower
text = re.compile(r"[A-Z]")
text.search(x)
if text.search(x) == None:
print("Your password needs to contain at least one Upper and lower case characters")
else:
break

# at least 1 digit
text = re.compile(r"\d+")
text.search(x)
if text.search(x) == None:
print("Your password needs to contain at least one number")
else:
print("Strong password")

x = input("press ENTER to quit")
if x == "":
print("Quitting...")
sys.exit()

passWordDetect(x)

Answer 1

"break" is used only in loops.

Answer 2

Ahh thank you

Answer 3

Unnecesssary breaks. No loops no breaks