How to print floating value of only last 2 round points in c++?

Question

Here suppose a is float a = 500/33;
If now I print a with c++ code
cout << a;
It will print 15.1515
But I just want to print only 15.15
Only the last 2 digits after the frictional period.
Is there any alternative?
NB: I would not like to use printf function.
https://code.sololearn.com/cOqhJD7ZY5nR/?ref=app

Answer 1

You forgot to
#include <iomanip>

Answer 2

1. Multiply by 100
2. Convert to int
3. Divide by 100.0

Answer 3

Yes, there are many more options, this was the simplest.

https://stackoverflow.com/questions/25925290/c-round-a-double-up-to-2-decimal-places

Answer 4

How to print floating value of only last 2 round points in c++?

Answer 5

I got a new idea. Thanks a lot.
cout << fixed << setprecision(2); cout << gpa; from this code.

Answer 6

Problem solved.
https://code.sololearn.com/cOqhJD7ZY5nR/?ref=app