double tuple trouble (in Python)

Question

Oh, these pesky yet incredibly useful little tuple.s
My problem is a list of tuples where I need to access
each one with my input. Then I need my input to match
(or not) with its' pair in a tuple for my output. But
when I use this 'for' statement to unpack the tuple, it
reassigns my input. I've tried other methods (like, 'if')
but they require me to define one tuple variable type int.
But I'm not sure how to do that w/o referencing my input.
The OUTPUT below is the result regardless what string is
input. Any assistance would be of great help w/this days-
old head-scratcher...

bowling_team1 = [
('Rue', 87),
('Tara', 95),
('Joey', 102),
('Amanda', 73),
('Bobby', 88)
]
name = input()
for (name,score) in bowling_team1:
print(name, 'has', score, 'points')

OUTPUT
Rue has 87 points
Tara has 95 points
Joey has 102 points
Amanda has 73 points
Bobby has 88 points

Answer 1

Average American ,

I believe you have two different name variables, one in the global namespace and one inside the for loop. Try renaming the global one name_in or something. Then you can access it inside the for loop in case you want to compare name_in to name.

bowling_team1 = [
('Rue', 87),
('Tara', 95),
('Joey', 102),
('Amanda', 73),
('Bobby', 88)
]

name_in = input()

for (name, score) in bowling_team1:
if name == name_in:
print(name, 'has', score, 'points')

Answer 2

I suggest you to use dictionary in Python.. it's more appropriate for that

bowling_team1 = {
'Rue': 87,
'Tara': 95,
'Joey': 102,
'Amanda': 73,
'Bobby': 88
}

Answer 3

It is almost the same as the tuple exercise in the intermediate course.

Here are some pointers:

https://www.sololearn.com/discuss/3256032/?ref=app
https://www.sololearn.com/discuss/3245242/?ref=app
https://www.sololearn.com/discuss/3234991/?ref=app
https://www.sololearn.com/discuss/2841893/?ref=app
https://www.sololearn.com/discuss/2847972/?ref=app

Answer 4

bowling_team1 = [
('Rue', 87),
('Tara', 95),
('Joey', 102),
('Amanda', 73),
('Bobby', 88)
]
#optional. Display list of players.
print('players:')
for player in bowling_team1:
print(player[0], end=' ')
print()

name = input()
result = 'name not in bowling_team1'
for player in bowling_team1:
if name == player[0]:
score = player[1]
result = f'{name} has {score} points'
print(result)

Answer 5

or use dictionary to simplify the search.

bowling_team1 = {
'Rue': 87,
'Tara': 95,
'Joey': 102,
'Amanda': 73,
'Bobby': 88
}
#optional. Display list of players.
print('players:\n', *(name for name in bowling_team1))

name = input()
if name in bowling_team1:
print(f'{name} has {bowling_team1[name]}')
else:
print(f'{name} not in bowling_team1' )