Python all() function

Question

Why this statement return false?

lst = [5,5,5,5,5]
x = all(lst) == 5
print(x)

Answer 1

Oliver Pasaribu ,

to check if all values of a list follow a certain condition, we can use all() with a list comprehension:

lst = [5,5,5,5,5]
x = all(num == 5 for num in lst) # result is True

lst = [5,5,5,5,3,5]
x = all(num == 5 for num in lst) # result is False

Answer 2

The all() function checks that every element of an iterable has a "truthy" value. 5 is truthy, so the all() function returns True.
But True is not equal to 5.

Answer 3

Oliver Pasaribu there is no reason why a different Python interpreter should give a different answer to the SAME code. it should not.
Maybe the code was different. Can you show a screenshot and specifically which interpreter you tried?

Answer 4

Oliver Pasaribu ,

reference for all()
https://docs.python.org/3/library/functions.html#all

and for its companion, any()
https://docs.python.org/3/library/functions.html#any

Answer 5

The statement returns False because all(lst) evaluates to True since all elements in the list lst are truthy (non-zero). However, True is not equal to 5, so x becomes False. Therefore, the result of the statement print(x) is False.

Answer 6

I use other python interpreter and it return True. So in this identical case, sololearn python interpreter must return True too. What do you think Tibor Santa?

Answer 7

This problem has a common with assertion in c++ or Java may be?

Answer 8

No, this is like an assertion mechanism. It convince that all i in list store int value 5.