Please help me understanding the output. I posted output with code in the file attached.

Question

https://sololearn.com/compiler-playground/cPQh9i6zoiOA/?ref=app

Answer 1

"""
[1]
|
v
[1, 1, 2, 3, 4, 5]

[2]
|
v
[1, 1, 2, 2, 3, 4, 5]

[3]
|
v
[1, 1, 2, 3, 2, 3, 4, 5]

[4]
|
v
[1, 1, 2, 3, 4, 2, 3, 4, 5]

[5]
|
v
[1, 1, 2, 3, 4, 5, 2, 3, 4, 5]

"""

Answer 2

First to clear inside the loop print(h[i:i], '&', [i]) this line prints the empty slice h[i:i] which results in an empty list because i:i doesn't include any elements followed by an ampersand (&) and the current value of i inside a list ([i]). For example, when i is 1, it prints [] & [1]. Here, h[i:i] = [i] this line is a tricky one. It replaces the slice h[i:i] which is empty with a list containing the value of i. It inserts the value of i at position i in the list h. This operation effectively inserts i at index i in the list h.

Now hopefully you understand the output, When i is 1, the empty slice [] is printed, followed by &, and [1]. Then, the list h is modified to [1, 1, 2, 3, 4, 5]. When i is 2, similar process as above, but now 2 is inserted at index 2 in the list h. Now, h becomes [1, 1, 2, 2, 3, 4, 5]. The pattern continues until i reaches 5 with i being inserted at position i in the list h during each iteration.

At the end of the loop, h contains [1, 1, 2, 3, 4, 5, 2, 3, 4, 5].

Answer 3

h=[1,2,3,4,5]
for i in range(1,6):
print(h[i:i],'&',[i])
h[i:i]=[i]
print(i, ' ',h)

[] & [1]
1 [1, 1, 2, 3, 4, 5]
[] & [2]
2 [1, 1, 2, 2, 3, 4, 5]
[] & [3]
3 [1, 1, 2, 3, 2, 3, 4, 5]
[] & [4]
4 [1, 1, 2, 3, 4, 2, 3, 4, 5]
[] & [5]
5 [1, 1, 2, 3, 4, 5, 2, 3, 4, 5]

[Program finished]

Please explain