Why does this code give n instead of y?

Question

In one of the code challenges, there is this exercise, but I don't understand why the answer is n instead of y?

"What is the output of this code

a,b=[1,2],[1,2]
if id(a)==id(b):
print("y")
else:
print("n")

(Code by Paolo Di Paolo)"

Can someone please explain?

Thanks!

Answer 1

Gwendolyn Vervaeke ,

list `a` and list `b` are not the same object, so they have a different id.

run the code below to see this effect here:

a,b=[1,2],[1,2]
print(f'a: {a}, b: {b}')
print(f'id a: {id(a)}, id b: {id(b)}')
if id(a)==id(b):
print("y")
else:
print("n")

Answer 2

if you just want to compare if two lists have the same length, same values, and in the same order, you can do

a,b = [1,2],[1,2]

if len(a)==len(b) and all(x == y for (x,y) in zip(a,b)):
print('y')
else:
print('n')

Answer 3

Godslove Iwuamadi ,

this is not the place to say hello.

> *q&a* section is meant for raising coding related questions and discussions.

> anything else can be posted in the `feed` in the `community` section.

Answer 4

Hello