can someone find the error

Question

def safe_print_list(my_list=[], x=0):
i = 0
count = 0
while (i < x):
try:
print("{:d}".format(my_list[i]), end="")
count += 1
except (TypeError, ValueError, IndexError):
pass
i += 1
print("")
return count

my_list = [1, 2, 3, 4, 5]

nb_print = safe_print_list(my_list, 2)
print("nb_print: {:d}".format(nb_print))
nb_print = safe_print_list(my_list, len(my_list))
print("nb_print: {:d}".format(nb_print))
nb_print = safe_print_list(my_list, len(my_list) + 2)
print("nb_print: {:d}".format(nb_print))

Answer 1

The code runs as written. The only issue I see is that on the exception, you are not printing anything so you don't see a message when there is an error. The error is being trapped, as it should, but you don't output any messages regarding the error.

Try adding a print statements within your except block and see if that tells you what you need to know.

except (TypeError, ValueError, IndexError):
if TypeError:
print(TypeError)
if ValueError:
print(ValueError)
if IndexError:
print(IndexError)