Void functional void with bool function

Question

Hi

I have a function which has below as argument:

Void std::function(void)

If this is the case, how to pass a function pointer of function which returns bool and does not take argument.

Answer 1

You can use a lambda:

bool boolFunction() {
std::cout << "Running bool function\n";
return true;
}

int main() {
std::function<void()> func = []() {
boolFunction(); // Call the bool function, but remove return value
};

// Now call std::function(void)
func();
}

Or use a wrapper function instead:

void wrapper() {
bool result = boolFunction();
}

std::function<void()> func = wrapper;

Answer 2

In other words, can I have something which accepts both:

std::function<void()> and std::function<bool()>

I actually had many argument to function also but that I am taking care by passing argument to std::find. How to handle return type of function so that bool function() and void function() is also allowed to get called

Answer 3

Unfortunately, I might be not able to do this. Additional wrapper (void function where we just ignore return type and this void function calls bool function)is not something I am looking for.

Is there anyway which makes it very generic in first place ?