Difference between call by reference and call by address?

Answer 1

https://code.sololearn.com/c613pBjuPn1q/?ref=app

Answer 2

do you mean "pass by reference" and "pass by value"?

You can try to understand with this link:
https://en.wikipedia.org/wiki/Function_prototype

Answer 3

if I make program (the code below)

#include <iostream>
using namespace std;

void set(int x)
{
x = 1;
}
int main()
{
int n = 5;
set(n);
cout<<n;
return 0;
}

this code will output 5 **It's call pass by value**
this function doesn't reference the address of variable n.

Answer 4

Then I create program:

#include <iostream>
using namespace std;

void set(int &x)
{
x = 1;
}
int main()
{
int n = 5;
set(n);
cout<<n;
return 0;
}

Lets see this code ('&' is added in set function)
It will make output 1 because it reference the address of integer n.
And it will edit the value of variable n directly.

Answer 5

you can imagine :
my c++ programs run in rams memory
Then I run program
value of variable n in 2nd code is already in the ram...
Of course! integer n had the address to call it (edit value,read value)
'&' sign is refer to address of variable x (parameters)
Don't forget '''x = n''' because ''n'' is argument of ''x''.

Answer 6

Pass by reference: use the memory address of an object in order to compute on it directly.
Every calculation directly affects the object.

Pass by value: create a copy of an object to be used in your calcualtions. Original object is not affected by the calculations done on its copy.

Answer 7

@nithiwat
can you explain second code ?
how it is work on memory?
we are not passing address how it works? or access Another local variable