While casting how does converting from double to integer rounds off to lower value?

Question

Eg: 1.5 should round off to 2 and 2.65 should be rounded off to 3
Making the sum to be 5(2+3) but the int(x) and int(y) takes only 1+2 giving a sum 3.
Can someone explain me how?

Answer 1

using (int)x will return the integer part of x without the fraction part, i.e the the first integer < x.

if you want to get the first integer > x
you must use Math.ceil(x).

the below example show the difference between casting (int)x and the use of Math.ceil(x):

double x = 1.3;
int y, z;

y = (int)x;
z = (int)Math.ceil(x);

System.out.print(y);
System.out.print(z);
// out put will be
// y = 1
// z = 2

Answer 2

you can use built in function math.round(double) to convert 1.5 to 2 and then sum it