What are the contents of this array?

Question

int x [4];

for(int i=0; i <4; i++)
{
x [i]=i+1;

if (i>=2)
x [i-1]=×[i]+2;
}

//Display contents of x.
for (i=0; i <4; i++)
cout << x [i] << " ":

How would you solve this?

Answer 1

1 5 6 4

First of all there are a lot of syntax errors, which I am will assume to be correct.

x [i] = i+1 gives 1,2,3,4 as the numbers.
But, if i>=2, x [i-1]=x [i]+2
//x [1]=x [2]+2=3+2=5
//x [2]=x [3]+2=4+2=6

Giving the array, 1 5 6 4

Answer 2

Edited

Answer 3

Please show how you got that.

Answer 4

Makes sense, thank you!!