Why variable name did not declare with no in name?

Answer 1

compare and think the statements below: 1. no varname =12; 2. varname=12; 3. notype varname=12; 4. var varname=12. The keyword "var" just tell compiler that the statement is to declare variable "varname" and the value is 12. The type of variabe is assigned by compiler.

Answer 2

Please Write Question Properly, I didn't get It.