why out put = 1

Question

#include <iostream>
using namespace std;

int main() {

int a=2;
int b=3;
int c=a^b;

cout << c << endl ;
return 0;
}

Answer 1

^ is a bit-wise xor operator which return 1 when corresponding bits in two operand are different
0 ^ 0 = 0
1 ^ 1 = 0
0 ^ 1 = 1
1 ^ 0 = 1

2 = 0010
3 = 0011

Now 2 ^ 3 = 0 0 1 0
0 0 1 1
---------
0 0 0 1
Hope that helps