in python it is showing error. .

Question

for the following code it displaying error.output not getting as 15.why? >>> 5*03

Answer 1

Just to be more specific, numbers starting with 0 were interpreted as octal (base 8) constants in python2. This was changed in python3.

Answer 2

You don't have to type the triple angular brackets... it just symbolize the prompt at the command line interpreter (CLI)...

And if you want run this code as a file (or here in code playground, which virtualize a file, not a CLI), you need to explicit that you want display the result of an expression, by assigning it to a variable and/or send it as parameter of the print() function (in CLI, works also, but default behaviour is to log return value of expression evaluated.

Finally, as said in previous answers, the 0 directly before the 3 is invalid syntax in Python 3 (and code playground run Python 3) ^^

Answer 3

Simply put, python 3.5 does not support the syntax of having a 0 in front of an integer. It does however still work with floats.
Just use: 5*3

Answer 4

You're getting an invalid token error. If you want to represent a decimal use "." So 5 * 0.3

I'm not sure what you was trying to do but having the zero before the 3 is the problem.

Answer 5

Just do 5*3 and you'll get 15. A number starting with a 0 is only allowed in Python 2.