Amicable Pairs

Question

Amicable numbers are two different numbers so related that the sum of the proper divisors of each is equal to the other number. - wikipedia.

So, 220 and 284 are amicable pairs, because,
proper divisors of 220 are [1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110]

and sum of 220's proper divisors are
1 + 2 + 4 + 5 + 10 + 11 + 20 + 22 + 44 + 55 + 110 = 284

Again,
proper divisors of 284 are [1, 2, 4, 71, 142]

and sum of it's proper divisors are
1 + 2 + 4 + 71 + 142 = 220

I've written a code to check if given pair are amicable or not. Please comment about how to optimize my code or to make it better. Thank you.

https://code.sololearn.com/cQS73oi9YeyJ

PS: Insert your numbers as comma separated. Like '220, 284'

Also, the first 10 amicable pair numbers are:
(220, 284), (1184, 1210), (2620, 2924), (5020, 5564), (6232, 6368), (10744, 10856), (12285, 14595), (17296, 18416), (63020, 76084), and (66928, 66992)

Answer 1

Minor point. I'm not familiar with Ruby, but this expression:

sum_of_a_divisors == b && sum_of_b_divisors == a

is already a Boolean. So, you probably don't need a ternary "? true : false" after it.

Answer 2

https://code.sololearn.com/c7JanWTaQtoW/?ref=app

Answer 3

@Igor B, Wow, Good catch man, thanks :)
I've updated the code.

PS: can anybody please tell me how to reply to comments?