How to swap two numbers without using a third variable?

Question

it can be done using (+,-) and(*,/).

Answer 1

a, b = b, a

:D

Answer 2

You can also use the bitwise xor operator:

a ^= b;
b ^= a;
a ^= b;
// a and b are now swapped

Answer 3

/*swapping two numbers without temp variable.
Can also replace + with * and - with / */

#include <iostream>
#include<conio.h>
using namespace std;

int main() {
int a,b;
a=10;
b=20;
cout<<"a and b before swapping "<<a<<" "<<b<<endl;
a=a+b;
b=a-b;
a=a-b;
cout<<"a and b after swapping "<<a<<" "<<b;
return 0;
}

Answer 4

https://code.sololearn.com/cx2Zl437LAcu/?ref=app

Answer 5

https://code.sololearn.com/cASd5yJTSj7P/?ref=app

Answer 6

Can try this one out

Let a and be the two integers to be swapped

a = a * b;
b = a / b;
a = a / b: