create a function that when given list of integers, returns a list,where the first element is the count of positive numbers and the second element is the sum of negative numbers. NB: Treat 0 as positive.

Question

Functions that deal with data structures

Answer 1

def sum_by_sign(src):
dst = [0,0]
dst[0] = sum(filter(lambda x: x >= 0, src))
dst[1] = sum(filter(lambda x: x < 0, src))
return dst

numbers = list(map(int, input("enter numbers in single line, separated with spaces:\n").split()))
sums = sum_by_sign(numbers)
print("sum of positive elements: {0}".format(sums[0]))
print("sum of negative elements: {0}".format(sums[1]))

-------
I would use dictionary for output to access sums with keys like 'negatives', 'positives' or smth like that, instead of indices. It seems to make program more clear for understanding.

Answer 2

thank you Textobot, could you please assist with the one that uses dictionaries?

Answer 3

the same with dictionary:
----------------------------

def sum_by_sign(src):
dst = {'positive':0,'negative':0}
dst['positive'] = sum(filter(lambda x: x >= 0, src))
dst['negative'] = sum(filter(lambda x: x < 0, src))
return dst

numbers = list(map(int, input("enter numbers in single line, separated with spaces:\n").split()))

sums = sum_by_sign(numbers)
print("sum of positive elements: {0}".format(sums['positive']))
print("sum of negative elements: {0}".format(sums['negative']))