How to obtain sum of reciprocal of integers up to an input value?

Question

including the input value

Answer 1

#include<iostream>
using namespace std;
int main()
{
float sum=0;
int no,a[100];
cout<<"enter no of inputs";
cin>>no;
for(int i=0;i<no;i++)
{cin>>a[i];
sum+=1/a[i];}
cout<<sum;
return 0;
}

Answer 2

http://code.sololearn.com/cVqVoEaEmcrK

#include <iostream>
using namespace std;

double inverseSerieSum(unsigned int n) {
unsigned int i;
double sum;
sum = 0;
for (i = 1; i <= n; i++) {
sum += 1.0/i;
}
return sum;
}

int main() {
unsigned int n;
cin >> n;
cout << inverseSerieSum(n);
return 0;
}