In java,when System.out.println{12345+5432l} output is 17777.In these case L is char or string.and can sum with integers?

Question

what is possible ans?

Answer 1

???

Can you show me a code with that?

Answer 2

Ohh the same as rust

fn main() {
let x = 10i32;
}

Answer 3

You used the wrong bracket :>.

Anyway, L will make the number of type long.
So, 5432L is a long with the value of 5432.

Adding the numbers together gives you 17777. Of type long.
That's really it.

It's the same as doing:

float a = 12.5f; // 12.5 is a float
double b = 0.5; // 0.5 is a double
print(a+b);

All regular whole numbers are by default of type int.
So, the L was used to indicate that it is actually a long.

Answer 4

Or:
double var = 5 * 3d; // 15.0 (d -> double)

Answer 5

thank u for ur ans

Answer 6

@MrCoder
What's the i supposed to be? Int is the default whole number, there is no need for i.

Answer 7

@Restoring faith Late reply lol, Declaring numbers in Rust is unpredictable, it can be f32, i32, i64, i8, and many more