how to print the following pattern using while and for loops: 5#\r 45#\r 345#\r 2345#\r 12345

Answer 1

print(r'#\r '.join(list(str('12345'[4-i:]) for i in range(5))))

Answer 2

Why posting again same aswered question? @@

https://www.sololearn.com/Discuss/592649/how-to-print-the-following-pattern-in-JUMP_LINK__&&__python__&&__JUMP_LINK-5-n-45-n-345-n-2345-n-12345

for i in range(5,0,-1):
for j in range(i,6):
print(j,end='')
print()

Answer 3

# Mix both solutions ^^

for i in range(5,0,-1):
j = i
while (j<6):
print(j,end='')
j += 1
print()

# or:

i = 5
while (i):
j = i
for j in range(i,6):
print(j,end='')
print()
i -= 1

Answer 4

You say 'for' loop in your question, and 'if' isn't a loop @@

@Shreyas wrote: << how to print the following pattern using while and for loops: 5#\r 45#\r 345#\r 2345#\r 12345 >>

Answer 5

No needs of 'if' with a 'while' loop, neither a 'for' one ^^

Answer 6

i = 5
while (i):
j = i
while (j<6):
print(j,end='')
j += 1
print()
i -= 1

Answer 7

https://code.sololearn.com/cjDsYO46VVWz/?ref=app

Answer 8

this ans is for beginners

n = int(input())
i = 1
while 0 < i <= n:
j = n-i+1
while 0 < j <= n:
print(j,end='')
j = j + 1
print()
i += 1

Answer 9

this time it's using while and if loop

Answer 10

u only used while..I asked with both while and if

Answer 11

not for loop ...if and while

Answer 12

ok thanks