What is cin.ignore(10, '\n') in C++?

Question

Hello :)

Pls excuse my bad english skills.

In my Book for C++, theres everytime a cin.ignore(10,'\n'); at the end of the program.
I do understand, that it ignores the "Enter" or "\n" then i input something in cin.
But i dont quite understand, why it is 10? Its in every example in the book, with one cin >> number

:) I hope somebody can explain it properly.
Thanks in advance!

Answer 1

istream& ignore(streamsize n = 1, int delim = EOF);

The program "ignores" (extract and discard) n number of characters from the input stream, or, if the delimiting character is met before all n characters have been ignored.

As for why most books put 10 in place of n, there is no real reason. I standardise stuff at 512, '\n' - i.e. chances of my clients effing up the program by banging their heads on their keyboards are pretty high.

Answer 2

Wow,

Thanks again @Hatsy!

Answer 3

Ah, Thanks alot @Hatsy :D