PYTHON Def function prints itself?

Question

I am coding a multiple choice story but all the possible choices just got printed as they are defined one after another, my order doesn't work. What could be the problem or what may I do wrong?
https://code.sololearn.com/cOHgM8dfJMLi/?ref=app

Answer 1

The big problem is :
if second2() == "Knife" or "knife":

If I had parenthesis to show you how the computer interpret this line, it will give :
if (second2() == "Knife") or "knife":
Moreover, a none empty string is considered true so all your conditions are true. The solution could be one of those two :

solution 1 :
choice = second2()
if choice == "Knife" or choice == "knife":

solution 2 :
if second2() in ["Knife","knife"]:

Answer 2

https://code.sololearn.com/csC9nIM29565/?ref=app
I've cleaned up your tabs and removed a heap of extra spaces.
works better for me but I have only tested with input "knife"

Answer 3

Would be glad to help, but can I see the code please ?

Answer 4

do you have a game loop?
are you checking for input before proceeding to the next decision point?

Answer 5

Can't post the code now, will do later for sure. Ain't got a loop, yes the function which needs decisions asks for input

Answer 6

Secondly, python define a block by its indentation, so in

def f(a):
a+=1
if a == 2:
print(a)
the if statement is NOT in the function, it will be called when read

Last problem I spotted is that you forgot parenthesis sometimes when you called start

Answer 7

One last (I forgot it) problem is the start function
you do not store the input and the start function (once correctly indented) will call itself infinitely

Answer 8

Hey there thanks for all the help so far, I will soon try your Suggestions on the code. But why do my variables print itself immediately?
Start=input("Enter stuff:")

?

Answer 9

https://code.sololearn.com/cOHgM8dfJMLi/?ref=app

That's the code, please help ^^

Answer 10

First because start is the name of the function, and second because the line you wrote here is not in your code :)

def start():
input()

if start() ....

Answer 11

Okay okay haha but I mean in another code and even before I used start as a function in this one, I tried using it as a variable, but it didn't work it just printed itself as it was created, very weird, any idea?

Answer 12

if your code is only :

start = input("Some text :")

The only output on sololearn should be :
Some text :

Answer 13

Yes it is, but shouldn't I have to call it first?
The problem is, as I define it, it directly gets printed without me actually coding
print(start)

Answer 14

add
print(start)
and you'll see that start value was not printed

Answer 15

Add where?

Answer 16

And lastly I think my indentations are right.. Deleted the or's in the code too, still doesn't wodk