Is there a shorter way of getting all string permutations than the following?

Question

from itertools import accumulate, permutations

def str_perm(s):
return list(map(lambda x: list(accumulate(x))[len(x)-1], list(permutations(s))))

print(str_perm("abcd"))

Answer 1

Turns out accumulate can be replaced with join:

from itertools import permutations

def str_perm(s):
# '' - is an empty string here
return [''.join(p) for p in permutations(s)]

print(str_perm("abcd"))