String to dictionnary

Question

how do i trasform a string with ":" into a dictionnary in python
like
a = "b : 1,c:2"
be
a_dict = {b:1,c:2}

Answer 1

https://code.sololearn.com/cSt6Zz0X5A3s/?ref=app

i was suprised this worked xD

Answer 2

in the first method you create a new dictionary in each iteration

you loop and each time assign a new dictionary to the variable, overwriting the old one

Answer 3

I was debating whether you might want to do the final step yourself and Burey posted, so here's what I was fiddling with FYI.

# multi assignment
a = "foo:bar"
key,val = a.split(":")
print(key,val)

# list comprehension
a = "foo:bar,biz:baz"
myList = [entry for entry in a.split(",")]
print(myList)

# dictionary comprehension from list
a = ["foo:bar"]
myDict = {key:val for key,val in [entry.split(":") for entry in a]}
print(myDict)

# dictionary comprehension from string
a = "foo:bar,biz:baz"
dict = {key:val for key,val in [entry.split(":") for entry in a.split(",")]}
print(dict)

Answer 4

thank ya bro , i'm working on it on my way 😂😂

Answer 5

thank you ! 😎😎

Answer 6

@Burey why the first method shows tow separated dictionnaries , but the second shows them matched ?

https://code.sololearn.com/cATIb42I66zH/?ref=app

Answer 7

ah then the 2nd method matches them in one []
how can ii avoid the first method separation ?