Overloading Methods problem

Question

What is the output of this code?
static void Print(int a) {
Console.WriteLine(a*a);
}
static void Print(double a) {
Console.WriteLine(a+a);
}
static void Main(string[] args) {
Print(3);
}

Im am particularity confused with this question because can't 3 pass for an int and a double? I know in some programming languages, this program will cause an error because 3 could pass for an integer or double.

Answer 1

You can wrap the overloads inside a class to make it work like this:

using System;

namespace Testing
{
class OverloadIssue
{
static void Print(int a)
{
Console.WriteLine(a*a);
}

static void Print(double a)
{
Console.WriteLine(a+a);
}

static void Main(string[] args)
{
Print(3);
Print(3.1);
}
}
}

Output:
9
6.2

Hth, cmiiw

Answer 2

You can do Print((double) 3);
It explicitly converts 3 into a double before passing it as an argument.