Challenge: reverse an integer!

Question

hi!
here there is a new challenge for you: reverse an integer!

example:

input: 1234567890
output: 0987654321

i know, it is quite an easy challenge... but to make things a little more difficult you can only use math operations! built in functions, arrays, vectors or similar must not be used (easy anyway, don't worry :D)

code in any language you want and show us your skills!
happy coding :)

Answer 1

try it guys ☺

//works for every integer , doesn't matter wherther u put 0's in front or u enter negative integer

//by using 2 methods ::: loops and recursion ☺

//exceptions handled

https://code.sololearn.com/cX6szu5M3Lud/?ref=app

Answer 2

updated: now satisfies the challenge requirement.

original:
Piece of cake for ruby!

https://code.sololearn.com/cUiWb8ULQ2d9/?ref=app

Answer 3

thnx 😊😊@luca

Answer 4

JavaScript:
alert(prompt("").split("").reverse().join(""));

Answer 5

my c++ version 😃
https://code.sololearn.com/cxxCmyv3L0Xr/?ref=app

Answer 6

https://code.sololearn.com/c6kj7a6iHqM0/?ref=app

Answer 7

num = int(input("Enter an integer to reverse: "))

while num != 0:
print(num % 10, end='')
num //= 10

Answer 8

Integers don't show a "0" in front

Answer 9

@Pegasus you can skip leading zeros if you prefer
@Lord nice code, but the task is to use only math operators and not built in functions or vectors/arrays/similar :)

Answer 10

Will this do-->

https://code.sololearn.com/cf7jMi7E1x4R/?ref=app

Answer 11

@ChaoticDawg excellent solution, best one till now! exactly the challenge task!

Answer 12

I'm curious @Gaurav 😁

Answer 13

My try
https://code.sololearn.com/cIBjhNz05g62/?ref=app

Answer 14

I can try, but that 0 infront is not good

Answer 15

JS:
alert(
(1234567890+'').split('').reverse().join('')
)

Answer 16

Slight modification to my previous code that actually reverses the integer as a whole instead of printing out each individual digit in the loop:

num = int(input("Enter an integer to reverse: "))
rev_num = 0

while num != 0:
rev_num = (rev_num * 10) + (num % 10)
num //= 10

print(rev_num)

Answer 17

@Gaurav i like recursion 😁

Answer 18

Not the regular split().reverse().join() .

Not just numbers anything is reversed :)
https://code.sololearn.com/Wjc93gIlCiba/?ref=app

Answer 19

https://code.sololearn.com/c9RX6f34KcGR/?ref=app

Answer 20

Ah I went to sleep and couldn't do it