🙋🏆 Question : why the alphabets in address are get printed..?🏆🙋

Question

I am trying a code in cpp for displaying address of variable "X" of int data type....
my doubt is if I used format specifier as "%d" then why the address have characters in it...?

https://code.sololearn.com/cr8KvHkapn0m/?ref=app

Answer 1

To add to @Nick and @Vincent Blankfield clear responses, just know that pointers are always printed in hexadecimal if not casted

Answer 2

I thinl the value of x is 4232046 and the adress of the variable is 0x28ff1c

Answer 3

It's hexadecimal number. They go like this:
decimal hexadecimal
0 = 0
1 = 1
2 = 2
3 = 3
4 = 4
5 = 5
6 = 6
7 = 7
8 = 8
9 = 9
10 = A
11 = B
12 = C
13 = D
14 = E
15 = F

In C++ hex a prefix 0x is used to identify hex numbers. Like 0x11FF. Some calculators (like Windows one) have "programming" mode, where you can convert between hex, dec and other base numbers.

https://en.wikipedia.org/wiki/Hexadecimal

Answer 4

actually I have tried this code in c & I thought that if i used the format specifier %d then the address of variable should be contained only integers....not a single character in it..I mean..
expected o/p =137285 something like that
actual o/p= 13fc56e something like that

Answer 5

thanks to all..I got it