overloading function

Question

why below code result is error??
int printName(int a) { }
float printName(int b) { }
double printName(int c) { }

Answer 1

Overloaded functions should have same name and different parameter list. Parameter lists may differ in three ways.

1. number of parameters
(int a)
(int a, int b)

2. type of parameters
(int a)
(double a)

3. order of parameters
(int a, float b)
(float a, int b)

The given functions have same parameter lists, so these are not overloaded. When you call them, it'll create conflict due to same argument list.

Answer 2

that's not overloading

if you call

printName(15)

how can the compiler know which one to pick?

overloading means same name but different arguments

Answer 3

You have stated return types, int, float, and double, but don't have a return statement in the function, so an error occurs. Just change them to "void," and change the parameter types to different ones, and it will run fine.

Answer 4

Wait... a function with a return type specified that doesn't return anything works? OK I'm confused.

Answer 5

Oh, OK.

Answer 6

so why below code shows error ??!?!

#include <iostream>
using namespace std;

int printName(int a) { }
float printName(int b) { }
double printName(int c) { }

int main()
{

return 0;
}

Answer 7

could you please write code as above code and in conclusion , compile correct with no error ???

Answer 8

thank you

Answer 9

Oh , Yes ....
that was a great hint ....

Answer 10

so great
thank you for more details ...

Answer 11

Thait's it ...
thank you for your attention

Answer 12

Thank you for your reference