What the mistaks in this code to print the prime numbers .. And give me the true one ..thank you

Question

#include <iostream.h>
int main()
{
int n,s,p;
cout<< "enter number";
cin>>p;
for(n=1;n<=p;n++)
{
if (p%n!=0)
{
s=1
break ;
cout <<"not prime";
}
else
{
s=0
}
}
if(s==0)
cout <<"prime";

return 0;
}

Answer 1

sure I have the solution to this

Answer 2

No need for the using namespace std？and the break might be a mistake I think...

Answer 3

The code will never print because before printing anything you break out of the loop

Answer 4

I guess the code cannot run...

Answer 5

where can I send you a pic of the code

Answer 6

if(p%n ==0) print not prime number
else (p%n !=0) print prime number

Answer 7

just be simple your complicating things

Answer 8

how we can modefid it? 💔

Answer 9

🐸🐸

Answer 10

يا ريت تكتبلي التعديلات و مشكور

Answer 11

I don't understand Arabic too

Answer 12

اعمل كوبي بيست هون اذا بصير

Answer 13

😂😂😂😂😂 write here if you can

Answer 14

we need to fix all numbers below the the fixed number so if statement dont enough ..is not??

Answer 15

well I didn't understand your question? you want to check if a number is prime or not?

Answer 16

yes

Answer 17

We can

Answer 18

but break in if statment not for all program