Why does it reiterate my previous input in the while loop when I only input once or twice.

Question

if I input ' 0 0 5' it compiles it to 15. why not 5?
https://code.sololearn.com/c1h1iH5jxg0j/?ref=app

Answer 1

so basically it is the problem with cin it is considering last value for all other iteration.

0 0 5 is interprited as 0 0 5 5 5
0 5 0 is interprited as 0 5 0 0 0
so if you have not given enough cin values then it will consider last cin values for others.

so if give input 0 5 0 then also you will get output as 5.

Answer 2

can you please put sample code?

Answer 3

ooh I am sorry, that's a mistake

Answer 4

thank you Great Saga . you've been helpful

Answer 5

I have done that @ Saga.. thanks for informing.

Answer 6

hi, problem is with your input ... if you are giving input like this 0 0 5 then it will take input as 0 0 5 5 5 so you get output as 15.

if u give input like 0 0 0 0 5 then you will get output 5.

for proof please run below code and verify the cout prints...
#include <iostream>
using namespace std;

int main()
{
int num = 1;
int number;
int total = 0;

while (num <= 5) {
cin >> number;

cout<<" total = " << total << " number = "<<number<<endl;
total += number;
num++;
}
cout << "final ="<<total << endl;

return 0;
}

Answer 7

@Sammy, Always wel come.