Printing array with reference

Question

Can someone explain me why it is 7?
lst1 = [1,2,3,4]
lst2 = lst1
lst1 [0] = 7
print(lst2 [0])

Answer 1

lst1 = [1,2,3,4]
lst2 = lst1
lst1 [0] = 7
print(lst2 [0])
# list1 has a list of elements assigned to it
# list2 has assigned list1 so it has same elements as list 1
# list1[0]=7 it assign list1 1st element to 7
# list1 and list2 are same so when we update list1 the elements of list2 is also updated so 7 overwrite in both the list at 1st element
# print(list2[0]) it print the 1st elements at list2 which is 7 due to overwrite
so finally the output is 7

Answer 2

I don't know python, but I know few other languages, so I might be wrong,
arrays are stored with references , only one copy is shared with all , hence modifying one changes all the copies
this concept is common in most of the languages

Answer 3

thanks everyone, now I get it 😀

Answer 4

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