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\n command failure
Heres the program: prin("1. Can we print lists without any entities in it?") first = [] print(first) print("As you see we can. The command was:\n first = []\nprint(first)\n2. Can we print 2 lists in one line?") first = [1,2,3] second = [7,8,9] print(first,second) print("We can do it too. Now how it was done:") print("first = [1,2,3]") print("second = [7,8,9]") print("print(first,second)") print("3. Can > or < use two numbers, or more?") if 20 > 15 and 5: print("20 is bigger than 15 and 5") p
6 odpowiedzi
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I don't know much python but I added a backslash like this \n\ :
print("As you see we can. The command was:\n\
first = []\nprint(first)\n2. Can we print 2 lists in one line?")
and it works. But btw, I don't think you can use > or < to compare with two numbers at once, for example (20 > 15 and 30) gives the same result as (20 > 15 and 5) because it is equivalent with (20 > 15 and True).
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in other words, what Paul means is that you pressed Enter after \n
I thought that was intentional, for esthetic reasons, and I added a backslash like in C++ to make it work :)
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and the \n crashes
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I have tried your code:
print("1. Can we print lists without any entities in it?")
first = []
print(first)
print("As you see we can. The command was:\nfirst = [] \nprint(first)\n2. Can we print 2 lists in one line?")
first = [1,2,3]
second = [7,8,9]
print(first,second)
print("We can do it too. Now how it was done:")
print("first = [1,2,3]")
print("second = [7,8,9]")
print("print(first,second)")
print("3. Can > or < use two numbers, or more?")
if 20 > 15 and 5:
print("20 is bigger than 15 and 5")
If you copy it like this it works. Somehow you pushed the new line key after the first \n.
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@paul Jacobs what is new line key
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It is also known as "enter" and on my keyboard it's sign is an arrow to the left.