is it possible

Question

x = 5;
y = ++x++;
// x is 6, y is 7

Answer 1

int y = ++x++;
// is equivalent to
int y = ++(x++);
// evaluates to
int y = ++(5);
and ++5 is not possible

The operand of an increment or decrement operator must be a variable, and here it is a constant so it is not possible

Answer 2

As a tip, to get your above statement to work, you may add brackets like this:

int y = (++x)++;

This works as ++x is still an lvalue while x++ is a rvalue. Since you can only perform increment on an lvalue and not on an rvalue, this works.

For details on why ++x is an lvalue and x++ isn't, visit this:

https://stackoverflow.com/questions/371503/why-is-i-considered-an-l-value-but-i-is-not