Simple code, output known, still confused.

Question

int result = 0;
for ( int i = 2; i < 5; i++ )
{
result = result + i;
}

I know the output is 9, but I simply just cannot get my head around how it works, even though it's simple code.

Please explain to this retard why the output is 9, thank you.

Answer 1

int result = 0; // set result as 0

for (int i = 2; i<5; i++){
//let i = 2;
//Run the for loop till i is less than 5 means exit the loop when i == 5;
//i++ add 1 to i when the loop runs but will return the previous value of i due to post-increment

result = result + i;
//assign result variable to itself + i
// so
/*
//1st run
result = 0 + 2 //now result is 2
//2nd run
result = 2 + 3 //result is 5
//3rd run
result = 5 + 4 //result is 9
// i == 5 now exit the loop
*/
}

Answer 2

put a couple of outputs in the loop. everything will become clear.

I.e
cout << result << " + " << i;
result = result + i;
cout << "=" << result << endl;

Answer 3

ty for the explanation Lord Krishna <3 easily understood.

I feel smarter now for understanding it, but dumber for not seeing it first time.
Love/hate rships tell me abt it

Answer 4

ty for the help jay :)