What kind of math is happening in my code?

Question

I wrote a code and cont make sense of all its output. If you can understand it please inform me.

https://code.sololearn.com/ct9cJCmbTrhw/?ref=app

thankyou.

Answer 1

I've take a look, not found any problem in your code, remember while loop just stop repeat doing when the condition of it false. And for loop either. Your for loop run 2 times, in the second time of for loop it changes the value to 324 in the first while. And become 40 in the second while( in second while it have to run 3 time to satisfy the condition of while loop, that why we have 40.)

Answer 2

given*=6; is given=given*6; is given=6*6; is given=36;
while(given<11) is false so loop exits
given/=2; is given=given/2; is given=38/2; is given=18;
while(given>40) is false so loop exits
given*=3; is given=given*3; is given=18*3; is given=54;
while(given<20) is false so loop exits
for(int x=given;x<8;x++) increments x to 7 and continues
given*=6; is given=given*6; is given=54*6; is given=324;
while(given<11) is false so loop exits
given/=2; is given=given/2; is given=324/2; is given=162;
while(given>40) is true so loop continues for 81 and 40 before exiting
given*=3; is given=given*3; is given=40*3; is given=120;
while(given<20) is false so loop exits
for(int x=given;x<8;x++) increments x to 8 and exits

Answer 3

input of -1 causes given*=6 and while(given<11) to loop until overflow to positive number or timeout.