[challenge] calculate squares between 41 and 59 ---mental arithmetic

Question

The squares ot these numbers (num) are easy
25 + (num -50) and num**2 as 2digit

example:
53**2

25 + 3 =28 3**2 = 9 --> 2809

example:

42**2
25-8 = 17 8**2 = 64 -->1764

find out how to adapt that "trick" for squares
in [35,65]and print the way how to calculate for that numbers similiar to examples.

all weapons welcome.
have fun

Answer 1

@vijay full power, if last digit is 1:

41 4**2|2*4|1 = 1681
71 7**2|2*7|1 =49|14|1 = 5041

Answer 2

Example solution for 41 -59
https://code.sololearn.com/cAbXqSBHvF7b

Answer 3

@xdeath:

I mean a kind of list

37**2 = ... :25+13 and 13**2 ...last step...

for all squares in[35,65]
the exact output is free but should demonstrate the "trick"

no userinput required
edit: why not user input?
user input a number and output explenation how to calculate,

challenges are ment as inspiration

Answer 4

@xdeath
sure: find all squares up to 10000 where each digit occurs not more than 1 time.

example 12* 12 = 144 not valid.... 4 occurs twice
13 * 13 = 169 valid no double digits

Answer 5

do you mean a system which will take user input and square it?

Answer 6

I'm new to coding is there a simpler challenge I could try?

Answer 7

@Donna wow nice code its compact and fast.I'm more of a JavaScript coder but still that's a fantastic code.works well too.

Answer 8

Also, there is another method for all two digit numbers.

suppose the number is 63.

1) 3*3 = 9
2) 2*6*3 = 36 ...keep 6 and pass 3 to the next part.
3) 6*6 = 36 +3 = 39
result = 3969

second number 56
1) 6*6 = 36 ..keep 6 n pass 3 to next
2) 2* 5*6= 60+ 3= 63..keep 3
3) 5*5 = 25 + 6= 31
result = 3136

https://code.sololearn.com/cAQ2344TVu27/?ref=app

Answer 9

@oma..ja, gut Abkürzung👍