[Challenge] Leap-year check

Question

Write a program that gets an input year and tells the user if this year is a leap-year.

Wikipedia quote:
"In the Gregorian calendar, each leap year has 366 days instead of the usual 365, by extending February to 29 days rather than the common 28. These extra days occur in years which are multiples of four (with the exception of years divisible by 100 but not by 400)."

Answer 1

https://code.sololearn.com/c9xVV0L6XY4q/?ref=app

Answer 2

https://code.sololearn.com/c7VMXRWuJ4l7/?ref=app

Answer 3

https://code.sololearn.com/chuo7IkL91Rw/?ref=app

Answer 4

https://code.sololearn.com/cAI0n3syD74I/?ref=app

Answer 5

https://code.sololearn.com/cQ1cVU65RDGr/?ref=app

Answer 6

https://code.sololearn.com/cl5PGtX5eomZ/?ref=app

Answer 7

https://code.sololearn.com/c2Zf0s4xb5Yd/?ref=app
there it is....😎

Answer 8

https://code.sololearn.com/cHuog2w1R1Nh/?ref=app

Answer 9

print("non-leap year"[(y%4==0 and (y%100!=0 or y%400==0))*4:])

Answer 10

https://code.sololearn.com/ceZIIX6hdSjv/?ref=app

Answer 11

https://code.sololearn.com/cG3SZJ967wz9/?ref=app

Answer 12

Hello, everyone! Here is my oneliner in python.
Please leave your comment and upvote!

https://code.sololearn.com/coFa3vGOZ579/

Answer 13

The leap year check is part of this code which returns your age in days.

https://code.sololearn.com/cBL0khFXj96K/?ref=app

Answer 14

y = int(input())
if y % 4 == 0:
if y % 100 == 0 and y % 400 != 0:
print("False")
else:
print("True")
else:
print("False")