C++ Prototype Declaration not working in my code?

Question

https://code.sololearn.com/cpkwZ1afYcJi/#cpp

#include <iostream>
#include <string>
using namespace std;

void allChecked();
void sike();

int main()
{

string nameString;

cout << "What is your name?" << endl;
cin >> nameString;
if(nameString == "Winson")
{
int password = 1316;
int passwordInteger;
cout << "You're awesome ;)" << endl;
cout << "What is the password?" << endl;
cin >> passwordInteger;

if(passwordInteger == password)
{
string favoriteArtist = "Frank Ocean";
string artistString;
cout << "Correct, you may continue." << endl;
cout << "Who's your favorite artist?" << endl;
cin >> artistString;

if(artistString == favoriteArtist)
{
allPassChecked();
}
else
{
sike();
}

}
else
{
cout << "Imposter!" << endl;
}
}
else
{
cout << "And you are?" << endl;
}
}
void allPassChecked()
{
cout << "You are you, lol" << endl;
}

void sike()
{
cout << "Sike!" << endl;
}

When I'm declaring the functions as prototype above the main functions, the compiler reacts by saying it is not defined in the scope? Why is this?

Answer 1

Your forward declaration does not match your function

allChecked != allPassChecked

Answer 2

:) It's an easy mistake to make. Don't feel too bad, we have all made such an error before.

Answer 3

That’s embarrassing, thank you! I looked it over and over but for it to be a syntax error...