Will the following code compile?If yes, then is there any other problem withthis code?

Question

#include<stdio.h>
void main(void)
{

char *ptr = (char*)malloc(10);
if(NULL == ptr)
{

printf("\n Malloc failed \n");
return;
}
else {

// Do some processing
free(ptr);
}
return;

Answer 1

No, it give you a good amount of error messages. Use, now a days int main() is used in c as well as c++. This is standard, you can search on google. Anyway

#include <stdio.h>
#include <stdlib.h>

int main()
{

char *ptr = (char*)malloc(10);
if(ptr==NULL)
{

printf("\n Malloc failed \n");
return 0;
}
else {

// Do some processing
free(ptr);
}
return 0;
}

Also There is no output in your program. if ptr is not null. And I want to add something. use
if(!ptr) it us equivalent to if(ptr==NULL)

Answer 2

There wil be a warning not error...
That we should use int return type instead of void..
And i appreciate your answer
.. Thank you.