smallest number

Question

def smallest():

num_1=float(input("Enter your first number:"))
num_2=float(input("Enter your second number:"))
num_3=float(input("Enter your third number:"))

if (num_1<=num_2) and (num_1<=num_3):
smallest=num_1
elif (num_2<=num_3) and (num_2<=num_1):
smallest=num_2
else:
smallest=num_3

print ("The smallest number is:",smallest)

smallest()

this code do not run .its show problem in 14 line. how can slove it ..what problem of my code?

after run the program show that (NameError: name 'num_1' is not defined

Answer 1

I got an error stating that on line 14, there is a syntax error. This is because after the part in quotations in your print function, you're supposed to have a plus (+) sign seperating the variable and the string. Also, when printing a variable, you can only print it if it is a string, so it might help to surround the variable name in the print function in a str() function.

Hope this helped!

Answer 2

This works:
https://code.sololearn.com/caWj84cnHPQe

Answer 3

Link your code by hitting share and copy link. Followed, by pasting link into a post. OR use + Insert button on the apps post popup. Without seeing it as coded, it looks like an indentation issue.

Answer 4

num_1 is not defined.. please anbody run the program of your computer than give me a pic

Answer 5

there is some indentation pblm...
just fix that...
like c, java python doesnt use {} for blocks of code...
it used indented blocks...
its importent to keep track of that...

fix that

Answer 6

indentation is ok ..this is no problem...

after run the program show that (NameError: name 'num_1' is not defined