+ 10
Try this code and explain what's going on !?
4 Respostas
+ 7
Import the regular expression library
1: import re
2:
Setup the string to process
3: str = "My name is David. Hi David."
Create a pattern to toss
4: pattern = r"David"
Overwrite the previous pattern with this one
5: pattern = r"."
Create an updated string to toss
6: newstr = re.sub(pattern, "Amy", str)
Overwrite the previous string with this one. Match every single character in the string we are processing and replace each one with 3 x's
7: newstr = re.sub(pattern, "xxx" , str)
Print the resulting string of x's
8: print(newstr)
+ 3
😂 You really like to strange codes don’t you? I’m afraid I can’t help you, but by the looks of things, you’re a few steps ahead of me in python.
+ 3
Given the pattern '.' that matches any characters except newline, so each character in your 'str' variable is replaced by 'xxx'.
+ 3
CODE WITH TRANSLATION:
import re
str = "My name is David. Hi David." # you created a string with 27 characters
pattern = r"David" # you created a variable named 'pattern' with the raw string 'David'
pattern = r"." # you changed the variable 'pattern' to '.' (this character matches any character except '\n')
newstr = re.sub(pattern, "Amy", str) # you substituted every character in str to 'Amy' and stored the result in newstr
# at this moment you have a string with 'Amy' repeating 27 times.
newstr = re.sub(pattern, "xxx" , str) # you substitued every character in str to 'xxx' and stored the result in newstr again
print(newstr) # you printed the value in newstr that is 'xxx' repeating 27 times
Hope I my translation is easy to understand.