An array a [ 2,3,4,1,4,0,4,5,3,3,1,0,590,32,45 1,0] . I want to make small arrays out of this.

Question

from array a I want to copy the elements into another array (say b) , until 0 is encountered. and then again continuing from the previous 0 found until next 0 comes the elements must get stored in another array say c, so how implement this ?
the output should be.
b [2,3,4,1,4]
c [4,5,3,3,1]
d [590,32,45,1]

Answer 1

You can do it this way:

currentArray = 0;

for(int i =0; i < mainArray.length;i++)
{
if (currentArray == 0){
if(mainArray[i]==0)
currentArray++;
else
b.push(mainArray[i]);
}
if (currentArray == 1){
if(mainArray[i]==0)
currentArray++;
else
c.push(mainArray[i]);
}

if (currentArray == 2){
if(mainArray[i]==0)
currentArray++;
else
c.push(mainArray[i]);
}
}

Answer 2

@Nahuel Ovejero

Awesome bro.!!! But many mistakes in the python code. The list:

---The syntax for 'for loop' is not right for python.Its as follows:
for i in mainArray:

---No curly braces and semi-colons throughout the code.

---In last if..else part its 'd.push(mainArray[i])' and not 'c.push(mainArray[i]'. Check Out.!!!

Answer 3

@MUTYALA SUBBARYUDU indeed, I was mistaken, thought it was C++ , but it was phyton!

Answer 4

thank you!

Answer 5

@MUTYALA SUBBARYUDU so in python does push array.push () work????
or should I use list.append for python?