list appends a list in python

Question

Can someone explain how it works?
x = [1,1,2,3,6]
x.append(x[:])
print(len(x))
outputs>>>>
6
x = [1,1,2,3,6,[...]]
What means this [...]?

Answer 1

are you sure it's x.append(x[:]) and not x.append(x) ?

Answer 2

Hechmi Barhouma
nope, x isn't the same as x[:]

x is the list instance itself, while x[:] should create a new identical list (duplicate the object)

the weird thing is this tho:
in your code you append x[:], which should result in the following list:
[1, 1, 2, 3, 6, [1, 1, 2, 3, 6]]

if you append x on the other hand, you should get this list:
[1, 1, 2, 3, 6, [ ... ]]

and that is because your x list is now contained in itself infinitely

[1, 1, 2, 3, 6, [1, 1, 2, 3, 6,[1, 1, 2, 3, 6, [1, 1, 2, 3, 6, [ ... ]]]]]

basically it would look like this
x --> [1, 1, 2, 3, 6, x ]
|________________|

Answer 3

oh great
glad it's clear ^_^

Answer 4

Yes sure,why?x[:] is in't the same as x Burey??

Answer 5

Ah thanks Burey,it is clear now.Good explanation.

Answer 6

What do you means Tianerad party game??

Answer 7

First of all the "len" keyword counts the number of items are there in the list as list can contain more list. and the "len" keyword considers it as a single item.

and second
x[:] is not same as x.
because
example: consider
x = [1,2]
b = x. output = [1,2]
c = x[:]. output = [1,2]
as you can see the output is same But the main difference is that
b is assigned to the same memory in which the value of x ([1,2]) is stored.
and c is assigned to the different memory for the same value of x ([1,2])